How do you graph the line that goes through #(3, 0)# and has a slope of #-3/4#?

1 Answer
Aug 31, 2016

Answer:

#y=-3/4x+c#

Explanation:

In the general equation of a line y=mx+c
m is the gradient and c is the value of the y intercept

So the equation of the line is #y= -3/4x +c#
This passes through (3,0)
So #0=-3/4*3+c#

So #c=9/4#
The equation of the line is

#y=-3/4x+9/4#

Or 4y=9-3x
graph{4y=9-3x [-10, 10, -5, 5]}