Question

How do you graph the line that goes through `(3, 0)` and has a slope of `-3/4`?

Answer 1

`y=-3/4x+c`

Explanation:

In the general equation of a line y=mx+c
m is the gradient and c is the value of the y intercept

So the equation of the line is `y= -3/4x +c`
This passes through (3,0)
So `0=-3/4*3+c`

So `c=9/4`
The equation of the line is

`y=-3/4x+9/4`

Or 4y=9-3x
graph{4y=9-3x [-10, 10, -5, 5]}