How do you graph the line that passes through (-1,5) perpendicular to the graph #5x-3y-3=0#?
First, get the equation into the form
The gradient of the perpendicular line is the negative reciprocal of the original line. The gradient of the original line is
Put this into the equation
The equation of the line is
Now for graphing.
You know the line passes through the point
You know that the y-intercept is
The gradient of the line is
Now you have 3 points, join them together and extend the line.