# How do you graph the line that passes through (3,3) perpendicular to the line y=3?

We have the graph of $y = 3$. The slope of this line is 0 and the y-intercept is 3. The line is also perpendicular to the x-axis. If the line we are looking for is perpendicular to $y = 3$ then our line is going to be perpendicular to the x-axis. A line that is perpendicular to the x-axis is $x = 0$. But, our line needs to go through (3,3). So we just add 3 to get the line $x = 3$.