# How do you graph the line through point (2,6) and slope m=2/3?

##### 1 Answer

#### Answer:

See a solution process below:

#### Explanation:

First, we can plot the point given in the problem:

graph{((x-2)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}

Slope is

The slope in the problem is

Therefore,

The change in the

The change in the

We can find another point by adding these to the values from the point in the problem:

We can now plot this point:

graph{((x-2)^2+(y-6)^2-0.1)((x-5)^2+(y-8)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a line through the two points:

graph{(y-2/3x - 4.6)((x-2)^2+(y-6)^2-0.1)((x-5)^2+(y-8)^2-0.1)=0 [-20, 20, -10, 10]}