Question

How do you graph the line `y= -2x+3`?

Answer 1

see explanation.

Explanation:

To graph a line we require 2 points.

The equation of a line in `color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`
where m represents the slope and b, the y-intercept.

`y=-2x+3" is in this form"`

`rArr"y-intercept "=b=3to(0,3)color(red)" is point on line"`

To find another point on the line, choose any value for x, substitute into the equation and evaluate for y

`x=3toy=(-2xx3)+3=-6+3=-3`

`rArr(3,-3)color(red)" is a point on the line"`

Plot the 2 points, draw a straight line through them to obtain the graph.
graph{-2x+3 [-10, 10, -5, 5]}