How do you graph the line #y=2x-5#?

1 Answer

Answer:

See below:

Explanation:

The equation is in slope intercept form, where the general form is:

#y=mx+b#, with #m# = slope and #b# = the y-intercept.

One way to graph it is to first plot the y-intercept. We are given the #y# point as #-5# and since it's the y-intercept, #x=0#, so we have #(0,-5)#

We also know the slope, #m=2#. One way to think of slope is #"rise"/"run"#. In our case where slope is 2, we can "rise" 2 points for every point we "run" (or move right along the x-axis). With our first point at #(0,-5)#, we can apply the slope and "rise" 2 (from #-5# up to #-3#) and "run" 1 (from 0 to 1), giving us #(1,-3)# and our second point. Plot them and draw a straight line through them.

The graph will look like this:

graph{2x-5 [-13.35, 18.68, -8.41, 7.61]}