# How do you graph the line y=2x-5?

See below:

#### Explanation:

The equation is in slope intercept form, where the general form is:

$y = m x + b$, with $m$ = slope and $b$ = the y-intercept.

One way to graph it is to first plot the y-intercept. We are given the $y$ point as $- 5$ and since it's the y-intercept, $x = 0$, so we have $\left(0 , - 5\right)$

We also know the slope, $m = 2$. One way to think of slope is $\text{rise"/"run}$. In our case where slope is 2, we can "rise" 2 points for every point we "run" (or move right along the x-axis). With our first point at $\left(0 , - 5\right)$, we can apply the slope and "rise" 2 (from $- 5$ up to $- 3$) and "run" 1 (from 0 to 1), giving us $\left(1 , - 3\right)$ and our second point. Plot them and draw a straight line through them.

The graph will look like this:

graph{2x-5 [-13.35, 18.68, -8.41, 7.61]}