How do you graph using the intercepts for #4x-3y=-19#?

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Answer 1 · 2016-05-21T10:51:28

#y_("intercept") = +19/3#
#x_("intercept")=-19/4#

Mark you points and draw a straight line through them.

Think about where the graph axis cross. The y-axis is where #x=0# and the x-axis is where #y=0#

To find #y_("intercept")# set #x=0#

#color(brown)(4x-3y=-19)color(blue)(" "->" "4(0)-3y=-19)#

Divide both sides by #(-3)#

#y_("intercept")=(-19)/(-3) = +19/3#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

To find #x_("intercept")# set #y=0#

#color(brown)(4x-3y=-19)color(blue)(" "->" "4x-3(0)=-19)#

Divide both sides by +4

#x_("intercept")=-19/4#