How do you graph using the intercepts for #4x-3y=-20#?

1 Answer
Dec 20, 2015

Answer:

Plot the intercept points and draw a straight line through them.

Explanation:

x-intercept
when #y=0#
#color(white)("XXX")4x-3xx0=-20#
#color(white)("XXX")rarr x=-5#
point at #(-5,0)#

y-intercept
when #x=0#
#color(white)("XXX")4xx0-3y=-20#
#color(white)("XXX")rarr y=20/3 (=7 2/3)#
point at #(0, 7 2/3)#

Plotting the two points and drawing a line through them should give a graph of the form:
graph{(4x-3y+20)((x+5)^2+y^2-0.01)(x^2+(y-(20/3))^2-0.01)=0 [-9.6, 8.18, -1.484, 7.405]}