Question

How do you graph using the intercepts for `4x-3y=-20`?

Answer 1

Plot the intercept points and draw a straight line through them.

Explanation:

x-intercept
when `y=0`
`color(white)("XXX")4x-3xx0=-20`
`color(white)("XXX")rarr x=-5`
point at `(-5,0)`

y-intercept
when `x=0`
`color(white)("XXX")4xx0-3y=-20`
`color(white)("XXX")rarr y=20/3 (=7 2/3)`
point at `(0, 7 2/3)`

Plotting the two points and drawing a line through them should give a graph of the form:
graph{(4x-3y+20)((x+5)^2+y^2-0.01)(x^2+(y-(20/3))^2-0.01)=0 [-9.6, 8.18, -1.484, 7.405]}