# How do you graph using the intercepts for 4x-3y=-20?

Dec 20, 2015

Plot the intercept points and draw a straight line through them.

#### Explanation:

x-intercept
when $y = 0$
$\textcolor{w h i t e}{\text{XXX}} 4 x - 3 \times 0 = - 20$
$\textcolor{w h i t e}{\text{XXX}} \rightarrow x = - 5$
point at $\left(- 5 , 0\right)$

y-intercept
when $x = 0$
$\textcolor{w h i t e}{\text{XXX}} 4 \times 0 - 3 y = - 20$
$\textcolor{w h i t e}{\text{XXX}} \rightarrow y = \frac{20}{3} \left(= 7 \frac{2}{3}\right)$
point at $\left(0 , 7 \frac{2}{3}\right)$

Plotting the two points and drawing a line through them should give a graph of the form:
graph{(4x-3y+20)((x+5)^2+y^2-0.01)(x^2+(y-(20/3))^2-0.01)=0 [-9.6, 8.18, -1.484, 7.405]}