How do you graph using the intercepts for #5x + 2y = -2#?
1 Answer
Nov 9, 2015
Plot the intercept points and draw a straight line through them
graph{(5x+2y+2) ((x+2/5)^2+y^2-0.01)(x^2+(y+1)^2-0.01)=0 [-4.93, 4.934, -2.465, 2.465]}
Explanation:
The x and y intercepts give us two points on the line defined by the linear equation.
The x-intercept is the value of
Given
when
which gives the point
Similarly for the y-intercept
we get the point
