How do you graph using the intercepts for # - 5x + 7y = 11#?

1 Answer
Aug 30, 2016

Answer:

The points are (2,3), (-5,-2) and (9,8). bolded text

Explanation:

-5x + 7y = 11
or, 7y = 11 + 5x
or, y = #(11+5x)/7#
now put the value of y as + 3, - 2 & + 8
so, we get values of x are + 2, - 5 & + 9
hence the points are (2,3), (-5,-2) and (9,8). Put these into the graph paper.