How do you graph using the intercepts for #7x + 4y = 17#?

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Answer 1 · 2018-08-08T20:37:02

Put zero in for both x and y solve for the other variable and then graph ( X, 0) and (0,Y) Draw a line between the two intercepts.

# 7 xx 0 + 4y = 17#

# 4y = 17#

# (4y)/4 = 17/4 #

# y = 17/4 or 4 1/4#

# 7x + 4 xx 0 = 17#

# 7x = 17 #

# (7x) /7 = 17/7#

# x = 17/7#

Plot #( 0, 17/4)# and #( 17/7 ,0)#

Connect the two points.

graph{7x+4y=17 [-9.92, 10.08, -2.88, 7.12]}