Question

How do you graph using the intercepts for `8x+6y=1`?

Answer 1

Plot the two points for the intercepts and draw a line through them.

Explanation:

y-intercept
`color(white)("XXX")`the value of `y` when `x=0`
`color(white)("XXXXX")8*0+6y=1`
`color(white)("XXXXX")rarr y=1/6`
`color(white)("XXX")`the y-intercept gives us the point `(0,1/6)`

x-intercept
`color(white)("XXX")`the value of `x` when `y=0`
`color(white)("XXXXX")8x+6*0=1`
`color(white)("XXXXX")rarr x=1/8`
`color(white)("XXX")`the x-intercept gives us the point `(1/8,0)`

Plot these two points (you will want to use a magnified graphing grid):
graph{((x-1/8)^2+y^2-0.0001)(x^2+(y-1/6)^2-0.0001)=0 [-0.7216, 0.9644, -0.3086, 0.5344]}

Draw a straight line through these two points:
graph{(8x+6y-1)((x-1/8)^2+y^2-0.0001)(x^2+(y-1/6)^2-0.0001)=0 [-0.7216, 0.9644, -0.3086, 0.5344]}