How do you graph using the intercepts for #8x+6y=1#?

1 Answer
Jan 28, 2016

Answer:

Plot the two points for the intercepts and draw a line through them.

Explanation:

y-intercept
#color(white)("XXX")#the value of #y# when #x=0#
#color(white)("XXXXX")8*0+6y=1#
#color(white)("XXXXX")rarr y=1/6#
#color(white)("XXX")#the y-intercept gives us the point #(0,1/6)#

x-intercept
#color(white)("XXX")#the value of #x# when #y=0#
#color(white)("XXXXX")8x+6*0=1#
#color(white)("XXXXX")rarr x=1/8#
#color(white)("XXX")#the x-intercept gives us the point #(1/8,0)#

Plot these two points (you will want to use a magnified graphing grid):
graph{((x-1/8)^2+y^2-0.0001)(x^2+(y-1/6)^2-0.0001)=0 [-0.7216, 0.9644, -0.3086, 0.5344]}

Draw a straight line through these two points:
graph{(8x+6y-1)((x-1/8)^2+y^2-0.0001)(x^2+(y-1/6)^2-0.0001)=0 [-0.7216, 0.9644, -0.3086, 0.5344]}