How do you graph using the intercepts for # x-y=11#?

1 Answer
Nov 1, 2015

Answer:

First, you would find the #x# and #y# intercepts for the line. Then, you would connect a line through them.

The #y#-intercept is #(0,-11)#
The #x#-intercept is #(11,0)#
graph{x-11 [-10, 10, -5, 5]}

Explanation:

To find the #y#-intercept: make #x=0# and solve for #y#. Your intercept is a point of the form #(0,y)#.

To find the #x#-intercept: make #y=0# and solve for #x#. Your intercept is a point of the form #(x,0)#.

We have the equation #x-y=11#

For the #y#-intercept, let's set #x=0# and solve for #y#:
#0-y=11#
#-y=11#
#y=-11#
So the #y#-intercept is #(0,-11)#

For the #x#-intercept, let's set #y=0# and solve for #x#:
#x-0=11#
#x=11#
So the #x#-intercept is #(11,0)#

Now, you just plot these two on an #x-y# plane and connect a straight line through them:

graph{x-11 [-10, 10, -5, 5]}