# How do you graph using the intercepts for  x-y=11?

Nov 1, 2015

First, you would find the $x$ and $y$ intercepts for the line. Then, you would connect a line through them.

The $y$-intercept is $\left(0 , - 11\right)$
The $x$-intercept is $\left(11 , 0\right)$
graph{x-11 [-10, 10, -5, 5]}

#### Explanation:

To find the $y$-intercept: make $x = 0$ and solve for $y$. Your intercept is a point of the form $\left(0 , y\right)$.

To find the $x$-intercept: make $y = 0$ and solve for $x$. Your intercept is a point of the form $\left(x , 0\right)$.

We have the equation $x - y = 11$

For the $y$-intercept, let's set $x = 0$ and solve for $y$:
$0 - y = 11$
$- y = 11$
$y = - 11$
So the $y$-intercept is $\left(0 , - 11\right)$

For the $x$-intercept, let's set $y = 0$ and solve for $x$:
$x - 0 = 11$
$x = 11$
So the $x$-intercept is $\left(11 , 0\right)$

Now, you just plot these two on an $x - y$ plane and connect a straight line through them:

graph{x-11 [-10, 10, -5, 5]}