# How do you graph using the intercepts for x-y=-3?

Dec 9, 2015

Plot the intercept points and draw a straight line through them:
graph{(x^2+(y-3)^2-0.01)((x+3)^2+y^2-0.01)(x-y+3)=0 [-10, 10, -5, 5]}

#### Explanation:

x-intercept is the value of $x$ when $y = 0$
$\textcolor{w h i t e}{\text{XXX}} 0 - y = - 3 \rightarrow y = 3$
$\Rightarrow$ x-intercept is at $\left(0 , 3\right)$

Similarly
$\textcolor{w h i t e}{\text{XXX}}$y-intercept is at $\left(- 3 , 0\right)$