How do you graph using the intercepts for #x-y=-3#?

1 Answer
Dec 9, 2015

Answer:

Plot the intercept points and draw a straight line through them:
graph{(x^2+(y-3)^2-0.01)((x+3)^2+y^2-0.01)(x-y+3)=0 [-10, 10, -5, 5]}

Explanation:

x-intercept is the value of #x# when #y=0#
#color(white)("XXX")0-y=-3 rarr y=3#
#rArr# x-intercept is at #(0,3)#

Similarly
#color(white)("XXX")#y-intercept is at #(-3,0)#