How do you graph #(x-1)^2+(y-4)^2=9#?

1 Answer
Jul 8, 2015

Answer:

You find the centre, the vertices, and the endpoints of the function. Then you plot the graph.

Explanation:

#(x-1)^2 + (y-4)^2 = 9#

This is the standard form for the equation of a circle with centre at (#1,4#) and radius #sqrt9 = 3#.

This means that, to find the vertices, you go 3 units up from the centre and 3 units down.

Thus, the vertices are at (#1,7#) and (#1,1#).

To find the endpoints, you go 3 units left of the centre and 3 to the right.

Thus, the endpoints are at (#-2,4#) and (#4,4#).

Plot these points on a graph.

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Now draw a smooth circle through these four points.

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And you have your graph.