How do you graph #(x-1)^2+(y-4)^2=9#?
You find the centre, the vertices, and the endpoints of the function. Then you plot the graph.
This is the standard form for the equation of a circle with centre at (
This means that, to find the vertices, you go 3 units up from the centre and 3 units down.
Thus, the vertices are at (
To find the endpoints, you go 3 units left of the centre and 3 to the right.
Thus, the endpoints are at (
Plot these points on a graph.
Now draw a smooth circle through these four points.
And you have your graph.