# How do you graph (x+2)^2 + (y+1)^2 =32?

Feb 5, 2016

Circle with the center $\left(- 2 , - 1\right)$ and the radius $4 \sqrt{2}$.

#### Explanation:

What you have here is a circle equation.

The standard form of a circle equation is

${\left(x - {x}_{m}\right)}^{2} + {\left(y - {y}_{m}\right)}^{2} = {r}^{2}$

which describes a circle with the center point $\left({x}_{m} , {y}_{m}\right)$ and the radius $r$.

In your case, ${x}_{m} = - 2$, ${y}_{m} = - 1$ and

$r = \sqrt{32} = \sqrt{16 \cdot 2} = 4 \sqrt{2} \approx 5.66$

Thus, you can graph a circle with the center point $\left(- 2 , - 1\right)$ and the radius $\approx 5.66$:

graph{(x+2)^2 + (y+1)^2 = 32 [-15.54, 16.49, -8.36, 7.66]}