# How do you graph (x+2)^2 + (y+3)^2 = 4?

Aug 7, 2015

#### Answer:

You determine the centre, vertices, and endpoints. Then you plot the graph.

#### Explanation:

${\left(x + 2\right)}^{2} + {\left(y + 3\right)}^{2} = 4$

This is the standard form for the equation of a circle with centre at ($- 2 , - 3$) and radius $\sqrt{4} = 2$.

This means that, to find the vertices, you go 2 units up from the centre and 2 units down.

Thus, the vertices are at ($- 2 , - 1$) and ($- 2 , - 5$).

To find the endpoints, you go 2 units left of the centre and 2 to the right.

Thus, the endpoints are at ($- 4 , - 3$) and ($0 , - 3$).

Plot the centre , the vertices, and the endpoints on a graph.

Now draw a smooth circle through the four outer points.

And you have your graph.