# How do you graph #x - 2/3y = 1 #?

##### 1 Answer

First, let's rewrite this as *point-slope form* or

*subtract #x# on both sides*

*divide both sides by #-2/3#*

Now it's in *point-slope form* (

the reason I wanted it in this exact form is because it gives us valuable information: the

These are very helpful for graphing, buecause we really only need to points on the line to draw the rest of it. And we already have one, the

The

*subtract #2/3# on both sides*

*divide by #-2/3# on both sides*

So, now we have two pints:

Just to check our work, let's graph our equation. If we did everything correctly, the line should pass through the points

graph{y=-(2)/3x + 2/3}

We were right!