How do you graph #x^2+y^2+6x-8y+9=0#?
1 Answer
Feb 12, 2016
circle: centre(-3 , 4) and radius = 4
Explanation:
the general equation of a circle is
# x^2 + y^2 + 2gx + 2fy + c = 0# the equation here :
#x^2 + y^2 + 6x - 8y + 9 = 0#
compares with the general equation and is therefore a circle.by comparison of the 2 equations :
obtain: 2g = 6 → g = 3 , 2f = -8 → f = -4 and c = 9
centre = (-g , -f ) = (-3 , 4 )
and radius =
#sqrt(g^2 + f^2 - c) = sqrt((-3)^2+4^2-9) = sqrt16 = 4#
