Question

How do you graph `x^2 + y^2 - 8x - 6y - 11 = 0`?

Answer 1

Refer to explanation

Explanation:

The equation `x^2 + y^2 - 8x - 6y - 11 = 0` can be rewritten as follows

#(x^2-8x+16)+(y^2-6y+9)=11+16+9=> (x-4)^2+(y-3)^2=6^2#

which is a circle with center `(4,3)` and radius `r=6` hence