# How do you graph x^2 + y^2 - 8x - 6y - 11 = 0?

The equation ${x}^{2} + {y}^{2} - 8 x - 6 y - 11 = 0$ can be rewritten as follows
(x^2-8x+16)+(y^2-6y+9)=11+16+9=> (x-4)^2+(y-3)^2=6^2
which is a circle with center $\left(4 , 3\right)$ and radius $r = 6$ hence