# How do you graph #x^2+y^2-8x+6y+16=0#?

##### 1 Answer

Nov 1, 2015

is a circle of radius

#### Explanation:

The equation of a circle of radius

#(x-a)^2+(y-b)^2 = r^2#

We are given:

#0 = x^2+y^2-8x+6y+16#

#=x^2-8x+16 + y^2+6y+9 - 9#

#=(x-4)^2 + (y+3)^2 - 3^2#

So:

#(x-4)^2+(y+3)^2 = 3^2#

which is in the form of the equation of a circle of radius

graph{(x-4)^2+(y+3)^2 = 3^2 [-7.875, 12.125, -7.8, 2.2]}