Question

How do you graph `x^2 + y^2 + 8x - 6y + 16 = 0`?

Answer 1

`x^2+y^2+8x-6y+16=0`
is a circle with radius `3` and center `(-4,3)`

Explanation:

`x^2+y^2+8x-6y+16=0`

`rArr (x^2+8x+16)+(y^x-6ycolor(red)(+9)=0color(red)(+9)`

`rArr (x+4)^2+(y-3)^2=3^^2`
`color(white)("XXX")`which is the general form for a circle with center `(-4,3)` and radius `3`
graph{x^2+y^2+8x-6y+16=0 [-9.636, 4.41, -0.826, 6.196]}