How do you graph #x-4y=12# using intercepts?

2 Answers

Given straight line: #x-4y=12# can be re-written in intercept form as follows

#x/12-{4y}/12=1#

#x/12+y/{-3}=1#

The above straight line has x-intercept #12# & y-intercept #-3#

Take the x-intercept #12# units on x-axis & y-intercept #3# units on -ve y-axis & join both the end-points by a straight line to get the graph/plot

Jun 28, 2018

Answer:

#"see explanation"#

Explanation:

#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#"let y = 0, in the equation for x-intercept"#

#x=0rArr-4y=12rArry=-3larrcolor(red)"y-intercept"#

#y=0rArrx=12larrcolor(red)"x-intercept"#

#"plot the points "(0,-3)" and "(12,0)#

#"Draw a straight line through them for graph"#
graph{(y-1/4x+3)((x-0)^2+(y+3)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}