# How do you graph #x-4y=12# using intercepts?

##### 2 Answers

Given straight line:

The above straight line has x-intercept

Take the x-intercept

#### Explanation:

#"to find the intercepts, that is where the graph crosses"#

#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#"let y = 0, in the equation for x-intercept"#

#x=0rArr-4y=12rArry=-3larrcolor(red)"y-intercept"#

#y=0rArrx=12larrcolor(red)"x-intercept"#

#"plot the points "(0,-3)" and "(12,0)#

#"Draw a straight line through them for graph"#

graph{(y-1/4x+3)((x-0)^2+(y+3)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}