How do you graph #x=-5# using intercepts?

1 Answer
Jan 9, 2018

Answer:

See a solution process below:

Explanation:

The equation #x = -5# represents a vertical line.

This means for each and every value of #y# then #x# is equal to #-5#

Therefore, the #x#-intercept when #y# equals #0# is: #-5# or #(-5, 0)#

Because the value of #x# is also #-5# it will never equal #0# therefore there is no #y#-intercept.

We can graph the lines as:

graph{((x+5)^2+y^2-0.025)(0.000001y + 100000x+500000) = 0 [-10, 10, - 5, 5]}