# How do you graph x-y=3 using the x and y intercepts?

May 27, 2017

graph{x-3 [-0.392, 4.62, -3.096, -0.59]}

#### Explanation:

We can express any linear equation in $t w o$ variables
in the form
$\frac{x}{a}$+$\frac{y}{b}$=$1$
(here the $e q$ will be ($\frac{x}{a}$$- \frac{y}{b}$=$3$)
1.we want to find where the line intersects the y axis

1. automatically the $v a l u e$ of $x$ will become $0$
we are left with $-$$\frac{y}{b}$=$3$
by putting $b = 1$ we get $y = - 3$
the line intersects the y axis at $\left(0 , - 3\right)$
2. in the same way we can also find out here the line intersects the axis
it will be $\left(3 , 0\right)$

in terms of plotting the $e q u a t i o n$ we will $m a r k$ $t h e$ $t w o$
points on the x&y and draw a st line $t h r o u g h$ $t h e m$