How do you graph #x-y=3# using the x and y intercepts?

1 Answer
May 27, 2017

Answer:

graph{x-3 [-0.392, 4.62, -3.096, -0.59]}

Explanation:

We can express any linear equation in #two# variables
in the form
#x/a#+#y/b#=#1#
(here the #eq# will be (#x/a##-y/b#=#3#)
1.we want to find where the line intersects the y axis

  1. automatically the #value# of #x# will become #0#
    we are left with #-##y/b#=#3#
    by putting #b=1# we get #y=-3#
    the line intersects the y axis at #(0,-3)#
  2. in the same way we can also find out here the line intersects the axis
    it will be #(3,0)#

in terms of plotting the #equation# we will #mark# #the# #two#
points on the #x&y# and draw a st line #through# #them#