How do you graph # x - y = 4#?

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Answer 1 · 2018-03-29T12:07:20

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#0 - y = 4#

#-y = 4#

#color(red)(-1) * -y = color(red)(-1) * 4#

#y = -4# or #(0, -4)#

Second Point: For #y = 0#

#x + 0 = 4#

#x = 4# or #(4, 0)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.035)((x-4)^2+y^2-0.035)=0 [-10, 10, -7, 3]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x - y - 4)(x^2+(y+4)^2-0.035)((x-4)^2+y^2-0.035)=0 [-10, 10, -7, 3]}