How do you graph #y=-1/2cosx#?

1 Answer
ali ergin
May 4, 2017

#"the solution of your problem is on the figure"#

Explanation:

enter image source here

#"give random angle values to x such as "-pi,-pi/2,0,pi/2,pi,...#

#"for x="-pi" " rArr" "y=-1/2*cos(-pi)=0.5#
#"for x="-pi/2" " rArr" "y=-1/2*cos(-pi/2)=0#
#"for x="0" " rArr" "y=-1/2*cos(0)=-0.5#
#"for x="pi/2" " rArr" "y=-1/2*cos(pi/2)=0#
#"for x="pi" " rArr" "y=-1/2*cos(pi)=0.5#

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