How do you graph # y=1/2sin(1/2)x#?

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Answer 1 · 2018-05-10T02:34:53

As below.

Standard Form of Sine Function is #y = A sin(Bx - C) + D#

Given #y = (1/2) sin (1/2)x#

#A = 1/2, B = 1/2, C = 0, D = 0#

#Amplitude = |A| = 1/2#

#"Period " = (2pi) / |B| = (2pi) / (1/2) = 4pi#

#"Phase Shift ' = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{(1/2)sin(x/2) [-10, 10, -5, 5]}