How do you graph #y = 1/2x + 2# by plotting points?

1 Answer
Nov 25, 2017

The graph would look like this:
graph{1/2x+2 [-10, 10, -5, 5]}


Since the equation is already in the form of #y=mx+b#, we could easily graph this equation. Remember: #m# is the slope of the line while #b# is the y-intercept. Also, remember that m is #(rise)/(run)#.

Therefore, first, you would plot a point on the y-axis. Since the y-intercept is 2, you would plot it on (0,2).

Then, you would graph another point in a spot by moving two spaces to the right and one space up from your y-intercept. You can repeat the process if you want to.

If you want to plot a point that is located to the left side of the y-intercept, simply graph a point on the spot by moving one space down and two spaces to the left.

Lastly, you could connect the points and extend them.