How do you graph #y=1/2x-2# by plotting points?

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Answer 1 · 2018-03-04T18:25:58

See a solution process below:

To graph a linear equation you just need to plot two points and draw a straight line through them.

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (1/2 xx 0) - 2#

#y = 0 - 2#

#y = -2# or #(0, -2)#

Second Point: For #y = 2#

#y = (1/2 xx 2) - 2#

#y = 1 - 2#

#y = -1# or #(2, -1)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+2)^2-0.025)((x-2)^2+(y+1)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 0.5x + 2)(x^2+(y+2)^2-0.025)((x-2)^2+(y+1)^2-0.025)=0 [-10, 10, -5, 5]}