How do you graph # y=1/3x+2# by plotting points?

1 Answer
May 3, 2017

See explanation

Explanation:

#color(brown)("Note that as the slope is constant ("1/3") then this is a straight line graph")#

Build a table of values: Use different numbers for x than I have (gives you practice). Work out the #y#-values.
Choose multiples of #3# for whole number answers.

Tony B

I have chosen three points as a check. All of them should line up. If not then there is an error so you will need to check your calculations and plotting.

My table gives the points: #" "(x,y)->(-10,-1 1/3)"; "(0,2)"; "(10,5 1/3)#

Draw your axes for #x and y#

Chose an appropriate scale and mark the values on the #x and y# axis.

Use these scales to mark your points and label them.

Draw a straight line through all three points. Extend the line to the edge of the squared area of the graph paper.

Put a title/heading on the graph stating what the equation is.

Tony B