How do you graph # y=1+sin(1/2x)#?

1 Answer
Mar 29, 2018

Answer:

graph{1+sin(1/2x) [-10, 10, -5, 5]}

Explanation:

#Sin(x)# is the original
#sin(x)+1# moves it up one so every y value is moved up 1

#sin(1/2x)# effects the period and it doubles the period of the sine curve from being #2pi# to #4pi#

As the period#=(2pi)/B#

With B being #Asin(B(x-C))+D# or in this case #1/2#