# How do you graph #y=1-sin2x# over the interval #0<=x<=360#?

##### 1 Answer

Apr 27, 2017

#### Answer:

This is what the graph will look like.

graph{y=1-sin(2x) [-0.734, 4.852, -0.402, 2.39]}

#### Explanation:

You should think of this as three separate transformations of the function

Firstly we will write the function you are looking to sketch as

Working through from

Now we deal with the negative. Since this is outside the function it affects the y-axis, in this case a reflection about the x-axis. We now have

Finally we must make an addition outside the function, this again affects the y-axis and in this case is a translation vertically by 1.