# How do you graph y=1-sin2x over the interval 0<=x<=360?

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer

2
Alex P. Share
Apr 27, 2017

This is what the graph will look like.
graph{y=1-sin(2x) [-0.734, 4.852, -0.402, 2.39]}

#### Explanation:

You should think of this as three separate transformations of the function $f \left(x\right) = \sin x$.

Firstly we will write the function you are looking to sketch as $y = - \sin 2 x + 1$.

Working through from $\sin x$ the first transformation in an enlargement in the x-direction scale factor $\frac{1}{2}$ to give $\sin 2 x$. Effectively this increases the frequency by 2.

Now we deal with the negative. Since this is outside the function it affects the y-axis, in this case a reflection about the x-axis. We now have $- \sin 2 x$.

Finally we must make an addition outside the function, this again affects the y-axis and in this case is a translation vertically by 1.

Then teach the underlying concepts
Don't copy without citing sources
preview
?

#### Explanation

Explain in detail...

#### Explanation:

I want someone to double check my answer
• 16 minutes ago
• 17 minutes ago
• 19 minutes ago
• 20 minutes ago
• 11 seconds ago
• A minute ago
• 2 minutes ago
• 4 minutes ago
• 5 minutes ago
• 6 minutes ago
• 16 minutes ago
• 17 minutes ago
• 19 minutes ago
• 20 minutes ago
• Che
• Phy
• Cal
• Alg
• Ear
• Soc
• Psy
• Org
• Pre
• U.S
• Wor
• Ast
• Ast
• Bio
• Eng
• Geo
• Env
• Sta
• Ana
• Tri
• Pre