How do you graph #y=2-5tan(x+pi/3)#?

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Answer 1 · 2018-07-31T13:17:54

See graph and details.

#y = 2 - 5 tan ( x + pi/3 )#, asymptotic #x + pi/3 ne ( 2 k + 1 ) pi/2,#

#k = 0, +-1, +-2, +-3, ... rArr x ne ( k + 1/6)pi#

The period = #pi#

Zeros: #tan ( x + pi/3 ) = 2/5 rArr x + pi/3 = k pi + arctan (2/5 ),#

#k = 0, +-1, +-2, +-3,..#

#rArr x = ( k - 1/3 )pi + arctan ( 2/5 )#

See graph.
graph{(y-2+5tan(x+pi/3))=0[-20 20 -10 10]}