How do you graph #y=-22/(x+43)-17# using asymptotes, intercepts, end behavior?

1 Answer
Nov 4, 2016

Answer:

Explained below

Explanation:

Asymptotes:

As #x->-43, y-> -oo# hence x= -43 is a vertical asymptote.

Next, as #x-> oo, y->-17#, hence y=-17 is an horizontal asymptote.

The graph will cross y-axis at point (0, -17-22/43) that is (0, -753/43)

The graph would cross x-axis at point y=0 and x coordinate would be given by #-22/(x+43) -17=0# that is 17(x+43)=-22, #x= -22/17 -43= -753/17#.
The point would thus be ( -753/17,0).The graph would look like

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