Question

How do you graph `y=2sin(x - pi)`?

Answer 1

Sketch `y=sin(x)` then redraw replacing each `y` coordinate with `(-2)xxy`

Explanation:

`sin(x-pi) = -sin(x)`
`rArr 2sin(x-pi) = -2sin(x)`

The graph of `y_1=-2sin(x)` is identical to the graph of `y_2=sin(x)` except for any value of `x`, `y_1 = (-2)*y_1`

Graph of `sin(x)`
graph{sin(x) [-6.33, 13.67, -4.88, 5.12]}

Graph of `-2sin(x)`
graph{-2sin(x) [-6.33, 13.67, -4.88, 5.12]}