How do you graph # y=2sin(x+pi/2)-3#?

1 Answer
May 6, 2017

Answer:

This is relatively simple. See below.

Explanation:

  1. Find the parent function of the graph. This should be: #y= sinx#.
  2. Now, identify all the transformations applied to the graph:
    (a) Vertical stretch by a factor of 2
    (b) Horizontal shift to the left by #pi/2#
    (c) Vertical shift down by 3
  3. You can now graph, either by individually applying each transformation above or using a mapping formula. For instance,
    #(x,y) -> (x-pi/2, 2y-3)#
    #(0, 0) -> (-pi/2, -3)#
    #(1, pi/2) -> (0, pi-3)#
    etc.

After you've obtained all the points, you can graph.