How do you graph #y=3/2cos(1/2pix)#?

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Answer 1 · 2018-05-04T09:49:46

As below.

#y = A cos (Bx - C) + D# is the standard form

Given #y = (3/2) cos ((pi/2) x)#

#Amplitude = |A| = 3/2#

#"Period " = (2pi) / |B| = (2pi) / (pi/2) = 4#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{(3/2) cos ((pi/2)x) [-10, 10, -5, 5]}