How do you graph #y=3/2sinx# over #0<=x<=360#?

1 Answer
Aug 1, 2018

Below

Explanation:

#y=3/2sinx#

When written in the general form, #y=asin(nx)+b#
where
#a# is amplitude
#n# is used to find the period
#b# is the shift of the graph up/down by #b# units

Looking at #y=3/2sinx#, we can immediately tell that it has an amplitude of #3/2# and its period is #2pi# and there is no shift. In other words, it is the graph #y=sinx# but with an amplitude of #3/2# and not #1#.

graph{3/2sinx [-10, 10, -5, 5]}
Above is the graph #y=3/2sinx#