How do you graph #y = 3 + 4 sin (pi/2) (x-2)#?

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Answer 1 · 2015-11-14T16:18:17

First, distribute the #pi/2#

#y=4sin[(pi/2)x-pi]+3#

phase shift : The #-pi# results in a phase shift to the right #pi# units

period : The coefficient (#pi/2#) in front of x determines the period ...
#=(2pi)/(pi/2)=4#

vertical shift: 3 units up

amplitude #=4#

hope that helped

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