How do you graph #y =3 sin (x +(2pi)/3)#?

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Answer 1 · 2018-03-19T05:39:13

As Below.

#y = 3 sin (x + (2pi)/3) #

Standard form #y = A sin (Bx - C) + D#

#Amplitude = |A| = 3#

Period # = P = (2pi) / |B| = (2pi) / 1 = 2pi#

#"Phase Shift " = (-C) / B = -((2pi)/3) color(white)(aaa)# #((2pi)/3 "to the left")#

#"Vertical Shift " = D = 0#

graph{3 sin (x + (2pi)/3) [-10, 10, -5, 5]}