How do you graph #y=3/(x-2)+3# using asymptotes, intercepts, end behavior?

1 Answer
Apr 15, 2018

Answer:

okay

Explanation:

You know that there is a vertical asymptote since x cannot be 2.
Solving for y=0 you see that x=1 so the x-int is (1,0), when inserting 0 as the x value you see that the y-int is (0,1.5) and the end behavior is similar to the parent #1/x# or in other words since the denominator has an x value that is greater than the numerator the horizontal asymptote is at y=0, but that is shifted up 3 by the last transformation.