# How do you graph #y=(34x-2)/(16x+4)# using asymptotes, intercepts, end behavior?

##### 1 Answer

I have managed to present the rectangular hyperbola represented by your equation.. Vertical asymptote:

#### Explanation:

graph{(y-17/2) (x+1/4)+9/4=0 [-40, 40, -20, 20]}

By actual division and reorganization,

This represents athe rectangular hyperbola with asymptotes #y

=17/2 and x = -1/4#.

The center is at the common point

The graph would clarify these statements.

As

As

Not easy to see in the graph, the x-intercept is 1/68 and y-intercept

is

Note that the general equation of a rectangular hyperbola is of the

form

enabling us to read the equations of the asymptotes as