How do you graph #y= -3cos (2x-2pi) -2#?

Question

4170 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-16T02:02:27

As below.

Standard form of cosine function is #y = A sin (Bx - C) + D#

#"Given " y = - 3 cos (2x - 2pi) - 2#

#A = -3, B = 2, C = 2pi, D = -2#

#"Amplitude " = |A| = |-3| = 3#

#"Period " = (2 pi) / |B| = (2 pi) / 2 = pi#

#"Phase Shift " = -C / B = (- 2 pi) / 2 = - pi, color(red)(pi " to the LEFT"#

#"Vertical Shift " = D = -2#

graph{- 3 cos(2x - 2 pi) - 2 [-10, 10, -5, 5]}