# How do you graph #(y-4)^2+ (x-2)^2=1#?

##### 2 Answers

May 2, 2018

#### Answer:

A circle of radius 1, centred at the point

#### Explanation:

Note: a circle of radius

In this example:

So, our graph is a circle of radius 1, centred at the point

graph{(y-4)^2 + (x-2)^2 =1 [-3.04, 9.444, -0.925, 5.315]}

Jul 7, 2018

#### Answer:

See below:

#### Explanation:

The equation of a circle is given by

With center

From our equation

We know that our center is at

graph{(x-2)^2+(y-4)^2=1 [-2.924, 7.076, 1.44, 6.44]}

Hope this helps!