How do you graph #y+4=-5/2(x-3)#?
1 Answer
Sep 12, 2017
See a solution process below:
Explanation:
This is a linear equation. Therefore, first, solve for two points which solve the equation and plot these points:
First Point: For
Second Point: For
We can next graph the two points on the coordinate plane:
graph{((x-3)^2+(y+4)^2-0.239)((x-5)^2+(y+9)^2-0.239)=0 [-30, 30, -15, 15]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y+5/2x - 7/2)((x-3)^2+(y+4)^2-0.239)((x-5)^2+(y+9)^2-0.239)=0 [-30, 30, -15, 15]}