How do you graph y+4=-5/2(x-3)?

1 Answer
Sep 12, 2017

See a solution process below:

Explanation:

This is a linear equation. Therefore, first, solve for two points which solve the equation and plot these points:

First Point: For $x = 3$

$y + 4 = - \frac{5}{2} \left(3 - 3\right)$

$y + 4 = - \frac{5}{2} \cdot 0$

$y + 4 = 0$

$y + 4 - \textcolor{red}{4} = 0 - \textcolor{red}{4}$

$y + 0 = - 4$

$y = - 4$ or $\left(0 , - 4\right)$

Second Point: For $x = 5$

$y + 4 = - \frac{5}{2} \left(5 - 3\right)$

$y + 4 = - \frac{5}{2} \cdot 2$

$y + 4 = - 5$

$y + 4 - \textcolor{red}{4} = - 5 - \textcolor{red}{4}$

$y + 0 = - 9$

$y = - 9$ or $\left(5 , - 9\right)$

We can next graph the two points on the coordinate plane:

graph{((x-3)^2+(y+4)^2-0.239)((x-5)^2+(y+9)^2-0.239)=0 [-30, 30, -15, 15]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y+5/2x - 7/2)((x-3)^2+(y+4)^2-0.239)((x-5)^2+(y+9)^2-0.239)=0 [-30, 30, -15, 15]}