# How do you graph y=4 sin (2x -pi/3)?

The graph of $y = 4 \sin \left(2 x - \frac{\pi}{3}\right)$
will have the same form as the graph of $y = \sin \left(\theta\right)$
the amplitude will be $4$ instead of $1$
the period will be $\frac{2 \pi}{2} = \pi$
and the sine wave will be shifted by $\frac{\pi}{6}$ to the right.
(since $\sin \left(2 x - \frac{\pi}{3}\right) = \sin \left(0\right) \text{ when " x=pi/6" )}$