How do you graph $y = 4x + 3$ ?

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Answer 1 · 2016-03-16T21:53:56

The $y$ -intercept is $0,3$ , and the slope is $4$ .

We know that the $y$ -intercept is $3$ , and that means that we start there. From there, we rise 4 units and go over (run) 1 unit.

I got this information from $y=mx+b$ , where $x=$ slope, and $b=$ the $y$ -intercept.

How do you graph y = 4x + 3y = 4x + 3?